Equivalent mass of $K M n O_{4}$ , when it is converted to $M n S O_{4}$ , is:

M / 5

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M / 3

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M / 6

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M / 2

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Solution

The correct option is A $M / 5$
The oxidation state of $M n$ is changed from +7 to +2 when it is converted from $K M n O_{4}$ to $M n S O_{4}$
So the equivalent weight is $M / 5$ .
Hence option $A$ is correct

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