Equivalent mass of sugar is:

\frac{M}{11}

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\frac{M}{12}

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\frac{M}{22}

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none of these

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Solution

The correct option is D $\frac{M}{22}$
$1$ mole of sugar, $C_{12} H_{22} O_{11}$ contains $22$ $H$ atoms. Therefore, its equivalent weight is $\frac{M}{22}$ .

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