Equivalent resistance between (a) & (b) in the circuit can be obtained by:

\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + \frac{1}{R_{4}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{R_{e q}} = \frac{1}{R_{1}} - \frac{1}{R_{2}} - \frac{1}{R_{3}} - \frac{1}{R_{4}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R_{e q} = R_{1} + R_{2} + R_{3} + R_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N o n e o f t h e s e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + \frac{1}{R_{4}}$
In a parallel circuit, the voltage across each of the components is the same.
For parallel connection $\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + . . . . . . . . + \frac{1}{R_{n}}$
$∴ \frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + \frac{1}{R_{4}}$

Suggest Corrections