Equivalent weight of a bivalent metal is $37.2$ . The molecular weight of its chloride is

216.6

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148.8

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145.4

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172.8

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Solution

The correct option is C 145.4
$E q u i v a l e n t w e i g h t o f M^{2 +} = 37.2$
$T h u s, m o l a r m a s s o f M^{2 +} = 37.2 \times 2 = 74.4$
(Mol. wt. $=$ Eq. wt./valency)
$T h u s, m o l a r m a s s o f M C l_{2} = 74.4 + 71 = 145.5$

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