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Equivalent Mass

Equivalent we...

Question

Equivalent weight of :
(a) $H_{3} P O_{2} = \frac{m o l e c u l a r w e i g h t}{1}$
(b) $H_{3} P O_{3} = \frac{m o l e c u l a r w e i g h t}{2}$
(c) $H_{3} P O_{4} = \frac{m o l e c u l a r w e i g h t}{3}$
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Solution

Equivalent weight of an acid is based on number of ionisable protons which is called Basicity. Ionisable hydrogen in attached to electronegative atom as $O$ and $X (F, C l, B r, I)$
(a) $H_{3} P O_{2}$ has one ionisable hydrogen (monobasic acid)
$H_{3} P O_{2} ⇌ H_{2} P O_{2}^{-} + H^{+}$
Hence, equivalent weight=molecular weight
(b) $H_{3} P O_{3} (d i b a s i c) ⇌ H P O_{3}^{2 -} + 2 H^{+}$
Hence, equivalent weight $= \frac{m o l e c u l a r w e i g h t}{2}$
(c) $H_{3} P O_{4} (t r i b a s i c) ⇌ P O_{4}^{3 -} + 3 H^{-}$
Hence, equivalent weight $= \frac{m o l e c u l a r w e i g h t}{3}$
Ionised hydrogen (circled) are attached to oxygen atoms.

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Similar questions

H_{3} P O_{4}

is stronger oxidant than

H_{3} P O_{3}

but weaker acid than

H_{3} P O_{3}

.
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Q. Assertion :Equivalent weight of

N H_{3}

in the reaction ,

N_{2} \to N H_{3}

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is 28/6. Reason: Equivalent weight

= \frac{Molecular weight}{Number of electrons lost or gained per molecule}

Q. In the following reaction:

2 {N H}_{3} ⟶ N_{2} + 2 {N H}_{3}

Equivalent weight of

{N H}_{3}

= \frac{M o l e c u l a r w e i g h t}{y}

What is the value of

y

H_{3} P O_{4}

N a H_{2} P O_{4}

N a_{2} H P O_{4}

N a_{3} P O_{4}

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Q. Assertion :Equivalent weight of a base

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Equivalent Mass

Standard XII Chemistry

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