Equivalent weight of $C a C l_{2}$ is:

\frac{F o r m u l a w e i g h t}{2}

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\frac{F o r m u l a w e i g h t}{1}

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\frac{F o r m u l a w e i g h t}{3}

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\frac{F o r m u l a w e i g h t}{4}

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Solution

The correct option is A $\frac{F o r m u l a w e i g h t}{2}$
Equivalent weight of $C a C l_{2} = \frac{F o r m u l a w e i g h t}{T o t a l c a t i o n c h a r g e o r t o t a l a n i o n c h a r g e}$ $= \frac{F W}{2}$

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