Equivalent weight of $C u S O_{4}$ in terms of its molecular weight M in the following reaction is

M

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M / 2

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M / 4

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M / 8

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Solution

The correct option is B $M / 2$

$(E q u i v a l e n t w e i g h t) = \frac{M o l e c u l a r w e i g h t}{N O . o f . e l e c t r o n s l o s t o r g a i n}$ .
The charge on Cu ion in $C u S O_{4}$ is $+ 2$
So $(E q u i v a l e n t w e i g h t) = \frac{M}{2}$ .
Hence option B is correct.

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