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Stoichiometry

Equivalent we...

Question

Equivalent weight of $H_{3} {P O}_{2}$ is:

E

= M

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E

= \frac{M}{2}

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E

= \frac{M}{3}

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none of these

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Solution

The correct option is A $E$ $= M$
Equivalent weight= $\frac{M o l e c u l a r w e i g h t}{n - f a c t o r}$
n-factor for given acid is 1
Hence
Equivalent weight= $\frac{M}{1}$

Suggest Corrections

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