Question

Equivalent weight of iron in $F{e}_2{O}_3$ would be:
$(Fe=56)$

• A. $28$
• B. $56$
• C. $18.6$
• D. $112$

Answer 1

The correct option is C $18.6$

Equivalent weight definition: weight of substance requires to combine or displace $8-gram$ oxygen or $1-gram$ hydrogen.

One electron transfer is enough to displace and combine with hydrogen or oxygen

In $F{e}_2{O}_3$

The oxidation state of $Fe$ in $F{e}_2{O}_{3}is+3.$

It mean one third on $Fe$ mole is enough to combine with $8-gram$ of $O_2$ Therefore, the equivalent weight of iron in $F{e}_2{O}_3=\frac{55.8}{3}=18.6g$