Question

Equivalent weight of $K_{2}C{r}_2{O}_7$ as oxidant in acidic medium is:

• A. $24.5$
• B. $49$
• C. $147$
• D. $296$

Answer 1

The correct option is B $49$

In $K_{2}C{r}_2{O}_7$, oxidation state of $Cr=+6$

In acidic medium,

$C{r}^{+6}⟶C{r}^{+3}$

$\therefore$ Change of oxidation state of $Cr=3$

$\therefore$ Change of oxidation state of $K_{2}C{r}_2{O}_7=6$

$\therefore$ Equivalent weight of $K_{2}C{r}_2{O}_7=\frac{Molecularweight}{6}$

=$\frac{294}{6}$

=$49$