Equivalent weight of $M n O_{4}^{-}$ when it changes to $M n O_{2}$ in concentrated basic medium is ?

1/3

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1/4

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1/5

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1/6

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Solution

The correct option is A 1/3
Equivalent weight of $M n O_{4}^{-}$ when it changes to $M n O_{2}$ in concentrated basic medium is one-third of molar mass. The oxidation number of Mn changes from +7 (in $M n O_{4}^{-}$ ) to +4 (in $M n O_{2}$ ). The net change in the oxidation number is +3. Equivalent weight is the ratio of the molar mass to the change in the oxidation number.

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