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Chlorination

Equivalents o...

Question

Equivalents of ${C O}_{2}$ used per mol of $H_{2} O$ used is :

A

2

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B

3

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C

5

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D

6

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Solution

The correct option is A $2$
When $C O_{2}$ is added to water, it forms carbonic acid, $H_{2} C O_{3}$ . So each mole of $C O_{2}$ gives you two moles of acid. That would make the 44 / 2 = 22 g equivalent.
As per photochemical equation, it suggests that for 1 mol $H_{2} O$ there is 1 mol of $C O_{2}$ ,
So, as molar mass of $C O_{2}$ is 44 g/mol.
So, for 1 mol $C O_{2}$ , the number of equivalents = 44 / 22 = 2 equivalents.

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