The escape velocity from the earth is about $11 k m s^{- 1}$ . The escape velocity from a planet having twice the radius and the same mean density as the earth, is

The mass of the moon is 1/81 of earth's mass and its radius 1/4 that of earth. If the escape velocity from the earth's surface is 11.2 km/s ,its value for the moon...

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Escape velocity at surface of earth is 11.2Km/s. Escape valocity from a planet whose mass is the same as that of earth and radius 1/4 that of earth, is?

The correct option is C 22.4km/sAt a certain velocity of projection the body will go out of the gravitational field of the earth and will never return to the earth, this velocity is known as escape velocity.ve=√2GMeReThus escape velocity will get doubled.

Escape velocity at surface of earth is $11.2$ Km $/$ s. Escape valocity from a planet whose mass is the same as that of earth and radius $1 / 4$ that of earth, is?

The correct option is C $22.4$ km $/$ s
At a certain velocity of projection the body will go out of the gravitational field of the earth and will never return to the earth, this velocity is known as escape velocity.
$v_{e} = \sqrt{\frac{2 G M_{e}}{R_{e}}}$
Thus escape velocity will get doubled.