Escape velocity of a body of 1 kg mass on a planet is 100 m/sec. Gravitational Potential energy of the body at the Planet is

- 5000 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 1000 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 2400 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5000 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
- 5000 J

$v_{e} = \sqrt{\frac{2 G M}{R}} = 100 \Rightarrow \frac{G M}{R} = 5000$
Potential energy $U = - \frac{G M m}{R} = - 5000 J$

Suggest Corrections

Similar questions

Q. Escape velocity of a body of

1 k g

mass on a planet is

100 m / s

. Gravitational potential energy of the body at the planet is:

Escape velocity of a body on a planet is $100 m s^{- 1}$ . What is the gravitational potential energy of the body at the surface, if the mass of the body is $1 k g$ ?

The potential energy of a body of mass 3 kg on the surface of a planet is 54 joule. The escape velocity will be

Q. Potential energy of a

3 k g

body at the surface of a planet is

54 J

then escape velocity will be.

Q. The escape velocity of a body on a planet depend on

Join BYJU'S Learning Program

Escape velocity of a body of 1 kg mass on a planet is 100 m/sec. Gravitational Potential energy of the body at the Planet is

The correct option is A - 5000 J ve=√2GMR=100⇒GMR=5000 Potential energy U=−GMmR=−5000 J

The correct option is A
- 5000 J

$v_{e} = \sqrt{\frac{2 G M}{R}} = 100 \Rightarrow \frac{G M}{R} = 5000$
Potential energy $U = - \frac{G M m}{R} = - 5000 J$