Establish the relation between angular momentum and rotational kinetic energy

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Solution

Dear student,
$L (A n g u l a r M o m e n t u m) = I ω^{} K . E (R o t a t i o n a l) = \frac{1}{2} I ω^{2} K . E (R o t a t i o n a l) = \frac{1}{2} \times I ω \times ω K . E (R o t a t i o n a l) = \frac{1}{2} L ω R e g a r d s$

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Establish the relation between angular momentum and rotational kinetic energy

Dear student, L(Angular Momentum)=IωK.E(Rotational)=12Iω2K.E(Rotational)=12×Iω×ωK.E(Rotational)=12LωRegards

Dear student,
$L (A n g u l a r M o m e n t u m) = I ω^{} K . E (R o t a t i o n a l) = \frac{1}{2} I ω^{2} K . E (R o t a t i o n a l) = \frac{1}{2} \times I ω \times ω K . E (R o t a t i o n a l) = \frac{1}{2} L ω R e g a r d s$