Esterification of the acid ( $P$ ) with the alcohol ( $Q$ ) gives :

only one enantiomer

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a mixture of diastereomer

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a mixture of enantiomer

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only one fraction on fractional distillation

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Solution

The correct option is B a mixture of diastereomer

Esterification of the acid ( $P$ ) with the alcohol ( $Q$ ) will give ( $R$ configuration) a mixture of diastereomers. They are as shown above. Diastereomers are non-superimposable and not mirror images.

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Q. In the esterification

C_{2} H_{5} O H (l) + C H_{3} C O O H (l) ⇌ C H_{3} C O O C_{2} H_{5} (l) + H_{2} O (l)

an equimolar mixture of alcohol and acid taken initially yields under equilibrium, the water with mole fraction

= 0.333.

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an equimolar mixture of alcohol and acid taken initially yields under equilibrium,the water with mole fraction=0.333.calculate the equilibrium constant.

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Esterification of the acid (P) with the alcohol (Q) gives :

The correct option is B a mixture of diastereomerEsterification of the acid (P) with the alcohol (Q) will give (R configuration) a mixture of diastereomers. They are as shown above. Diastereomers are non-superimposable and not mirror images.

Esterification of the acid ( $P$ ) with the alcohol ( $Q$ ) gives :

The correct option is B a mixture of diastereomer

Esterification of the acid ( $P$ ) with the alcohol ( $Q$ ) will give ( $R$ configuration) a mixture of diastereomers. They are as shown above. Diastereomers are non-superimposable and not mirror images.