Estimate each difference to the nearest ten:
(409 − 148)

Open in App

Solution

409 estimated to the nearest ten = 410
148 estimated to the nearest ten = 150
∴ The required estimation = (410 ‒ 150) = 260

Suggest Corrections

Similar questions

Q. Estimate each difference to the nearest ten:
(53 − 18)

Based on Table 1, the balance on the current account is:

Table 1

$\begin{matrix} Exports of goods and services & 1000 Imports of goods and services & 800 Net change in assets owned abroad & 500 Net change in foreign owned assets at home & 400 Unilateral transfers received & 100 Unilateral transfers paid & 200 Investment income paid to foreigners & 300 Investment income received from foreigners & 400 \end{matrix}$

Q. Match the statement in column I with the results in column II

\begin{matrix} Column- I & Column - II (A) A variable resistor is connected across a non ideal & (P) First increases for some time cell. As the variable resistor is & and then decreases continuously increased from zero to a very large value, the electric power consumed by the variable resistor (B) A circular ring lies in space having & (Q) First decreases for some time uniform and constant magnetic field which & and then increases is parallel to plane of the ring. Keeping the centre of ring fixed, the rings is rotated by 180^{\circ} about one of its diameter which is perpendicular to magnetic field with constant angular speed. For the duration the ring rotates, the magnitude of induced emf in the ring (C) A thin rod of length 1 cm lies along & (R) is always constant principal axis of a convex lens of focal length 5 cm. One end of rod is at a distance 10 cm from optical centre of the lengs. The convex lens is moved (without rotation) perpendicular to initial principal axis by 5 mm and brought back to its initial position. Length of image of the rod (D) A bulb (of negiligible inductance) and a & (S) increases or may increase capacitor in series are connected across an & over some time interval. ideal AC source of constant peak voltage and variable frequency. As frequency of AC source is continuously increased, the brightness of bulb \end{matrix}

We don't go through the ground we stand on it because of this force. Name this force.

Q. Solve each of the following equations and verify the answer in each case:

\frac{n}{4} - 5 = \frac{n}{6} + \frac{1}{2}

Join BYJU'S Learning Program

Estimate each difference to the nearest ten: (409 − 148)

409 estimated to the nearest ten = 410 148 estimated to the nearest ten = 150 ∴ The required estimation = (410 ‒ 150) = 260

Estimate each difference to the nearest ten:
(409 − 148)

409 estimated to the nearest ten = 410
148 estimated to the nearest ten = 150
∴ The required estimation = (410 ‒ 150) = 260