Estimate the difference:
$H T O 7 3 0 - 2 1 7$

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Solution

Step 1: Subtract the ones
Given : $H T O 7 3 0 - 2 1 7$
As $7$ can not subtracted from $0$ ,
so, take $1$ carry from tens
now, $0$ becomes $10$ ( as $1$ carry taken from tens )
First subtract ones $10 - 7 = 3$ ,
Write $3$ under ones column
Step 2: Subtract the tens
$3$ becomes $2$ in hundreds ( as $1$ carry taken by ones)
Next subtract tens $2 - 1 = 1$ ,
Write $1$ under tens column
Step 3: subtract the hundreds
Next subtract hundreds $7 - 2 = 5$ ,
Write $5$ under hundreds column
So we get,
$H T O Carryover 2 10 7 3 0 - 2 1 7 5 1 3$
Hence, the required solution is $513$

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f (x) = 3 x^{10} - 7 x^{8} + 5 x^{6} - 21 x^{3} + 3 x^{2} - 7. Then lim h \to 0 \frac{f (1 - h) - f (1)}{h^{3} + 3 h}

Clues

Across Down

(a) $7^{3}$ (a) $6^{2}$

(b) $7 \times 3^{2}$ (b) $13^{1} \times 3^{1}$

(d) $7^{2}$ (d) $3^{2} \times 11$

(e) $2^{9}$ (e) $11^{2} \times 6^{0}$

(f) $10^{2} + 6$ (f) $2^{4}$

(g) $3^{6}$ (g) $3^{2} + 50$

(h) $11^{1} \times 2^{3}$ (h) $2^{3} \times 5^{1} \times 7^{1}$

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