Question

Estimate the difference in energy between I and II Bohr Orbit for a hydrogen atom. At what minimum at no. a transition from n=2 to n=1 energy level would result in the emission of X-rays with $\lambda =3.0x{10}^{8}m$? Which hydrogen like species does this at no correspond to.

Answer 1

Energy of $n^{th}$ orbit $=-E_0\times \frac{1}{n^2}$

Energy of $1$ orbit $=-E_0=-13.6$ $eV$

Energy of $2$ orbit $=\frac{-E_0}{4}=-3.4$ $eV$

$\therefore$ energy of difference$=10.2$ $eV$.