Question

Estimate the max. $pH$ that can be attained by dissolving methylamine in water.

Answer 1

$PV=nRT$
$1\times 0.959=n\times 0.0821\times 298$
$n=0.03919$
volume of $H_{2}O=1mL$ (per volume of $H_{2}O$)
$C=\frac{n}{V}=\frac{0.03919}{{10}^{-3}}=39.19M$
$p{k}_b=3.39$ $\Rightarrow$ $k_b=4\times {10}^{-4}$
$\left[{OH}^{-}\right]=\sqrt{K_{b}C}=0.1252M$
$pOH=0.9023$
$pH=13.097$