The correct option is A 10.99
We need to find 3√1333
Take, n=1333, choose any starting value of x.
So, 113 is 1331<1333
So, x=11
xnext = 23x+n3x2
xnext = 2311+13313×112
xnext =10.999 ....(1)
Assume x=10.99
xnext= 2310.99+13313×10.992
xnext=10.99 ....(2)
Since we are getting 10.99 in (1) and (2)
So, the approximate value of 3√1333 =10.99