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Question

Ethanoic acid on heating with ammonia forms compound A which on treatment with bromine and sodium hydroxide gives compound B. Compound B on treatment with NaNO2/dil.HCl gives compound C. The compounds A,B and C respectively are:

A
Ethanamide, methanamine, methanol
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B
Propanamide, ethanamine, ethanol
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C
N-ethylpropanamide, methaneisonitrile, methanamine
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D
Ethanamine, bromoethane, ethanediazoniumchloride
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E
Methanamine, ethanamide, methanol
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Solution

The correct option is A Ethanamide, methanamine, methanol
CH3COOH+NH3CH3CONH2ethanamideA

CH3CONH2A+Br2+3NaOHCH3NH2methylamine(B)
+Na2CO3+NaBr+H2O
CH3NH2HNO2−−−−−−−−−(NaNO2/diHCl)CH3OHmethanolC

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