Question

Ethanoic acid was added to sodium bicarbonate solution and the gas evolved was tested with a burning splinter. The following four observations were reported that:

The correct observation is reported in:

• A. The gas burns with a pop sound and the flame get extinguished
• B. the gas does not burn but the splinter burns with a pop sound
• C. the flame extinguishes and the gas does not burn
• D. the gas burns with a blue flame and the splinter burn brightly.

Answer 1

The correct option is C

the flame extinguishes and the gas does not burn

A functional group is defined as a group of atoms that exist in a molecule and describes the characteristics reactions of organic compounds is called a functional group.

The functional group present in carboxylic acid is $\mathrm{COOH}$.

The ethanoic acid (${\mathrm{CH}}_3\mathrm{COOH}$) is reacted with Sodium bicarbonate carbonate (${\mathrm{Na}}_2{\mathrm{CO}}_3$) to form Carbon dioxide (${\mathrm{CO}}_2$), Sodium acetate (${\mathrm{CH}}_3\mathrm{COONa}$), and water (${\mathrm{H}}_2\mathrm{O}$) as the final product.

The reaction that happens is written as follows:

$$\begin{gathered} {\mathrm{CH}}_3\mathrm{COOH}\left(\mathrm{l}\right)+{\mathrm{Na}}_2{\mathrm{CO}}_3\left(\mathrm{s}\right)\to {\mathrm{CH}}_3\mathrm{COONa}+{\mathrm{CO}}_2\left(\mathrm{g}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right) \\ (\mathrm{Ethanoic}(\mathrm{sodium}\mathrm{hydrogen}(\mathrm{sodium}(\mathrm{carbon}+\left(\mathrm{water}\right) \\ \mathrm{acid})\mathrm{carbonate})\mathrm{acetate})\mathrm{dioxide}) \end{gathered}$$

Observations:

Carbon dioxide ${\mathrm{CO}}_2$ gas is evolved immediately with brisk effervescence no pop sound is produced.

Carbon dioxide is a non-supporter of ignition it does not burn, So the carbon dioxide gas extinguishes the burning splinter that is brought near it.

Hence, option (C) is the correct option.