Ethanol boils at ${78.4}^{o} C$ and standard enthalpy of vaporization of ethanol is $42.4 k J {m o l}^{- 1}$ . Calculate the entropy of vaporization of ethanol.

60.9 J K^{- 1} {m o l}^{- 1}

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20.9 J K^{- 1} {m o l}^{- 1}

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120.6 J K^{- 1} {m o l}^{- 1}

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100.9 J K^{- 1} {m o l}^{- 1}

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Solution

The correct option is B $120.6 J K^{- 1} {m o l}^{- 1}$
we have,
$Δ H = T Δ S$
so, $Δ S = \frac{Δ H}{T}$
entropy of vaporization = $\frac{42400}{351.4} = 120.6$

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