Ethanol when reacted with $P C l_{5}$ gives (A), $P O C l_{3}$ and $H C l$ . (A) reacts with silver nitrite to form (B) (major product) and $A g C l$ . (A) and (B) are respectively.

C_{2} H_{5} C l

and

C_{2} H_{5} O C_{2} H_{5}

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C_{2} H_{6}

and

C_{2} H_{5} O C_{2} H_{5}

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C_{2} H_{5} C l

and

C_{2} H_{5} N O_{2}

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C_{2} H_{6}

and

C_{2} H_{5} N O_{2}

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Solution

The correct option is B $C_{2} H_{5} C l$ and $C_{2} H_{5} N O_{2}$
The required reactions are:

$C_{2} H_{5} O H + P C l_{5} ⟶ C_{2} H_{5} C l (A) + P O C l_{3} + H C l$

$C_{2} H_{5} C l + A g N O_{2} ⟶ C_{2} H_{5} N O_{2} (B) + A g C l$

Hence, option C is correct.

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