Ethyl alcohol forms $C a C l_{2} . X C_{2} H_{5} O H; M g C l_{2} . Y C_{2} H_{5} O H$ and $C u S O_{4} . Z C_{2} H_{5} O H$ when $C_{2} H_{5} O H$ reacts with respective respective anhydrous salts. Then?

X = 3, Y = 3, Z = 6

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X = 2, Y = 2, Z = 3

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X = 3, Y = 7, Z = 4

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X = 4, Y = 4, Z = 4

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Solution

The correct option is B $X = 2, Y = 2, Z = 3$
The reaction of ethyl alcohol with the following anhydrous salts give these products:
$C a C l_{2}$ + $2 C_{2} H_{5} O H$ → $C a C l_{2} . 2 C_{2} H_{5} O H$
$M g C l_{2}$ + $2 C_{2} H_{5} O H$ → $M g C l_{2} . 2 C_{2} H_{5} O H$
$C u S O_{4}$ + $3 C_{2} H_{5} O H$ → $C u S O_{4} . 3 C_{2} H_{5} O H$

Thus, X =2 , Y = 2 and Z = 3.
Option B is correct.

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