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Question

Ethyl alcohol on heating with HI in presence of ZnCl2 yields:

A
ethane
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B
ethyl Iodide
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C
ethylene
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D
methane
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Solution

The correct option is B ethyl Iodide
This is an example of a substitution reaction
ethanol in presence of ZnCl2 with HI undergoes carbocation formation which undergoes an attack by Inucleophile to ethyl iodide. Iattacks the substrate since its active concentrated is more n its a stronger nucleophile.

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