Ethyl benzoate reacts with $P C l_{5}$ to give :

C_{2} H_{5} C l + C_{6} H_{5} C O C l + P O C l_{3} + H C l

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C_{2} H_{5} C l + C_{6} H_{5} C O C l + P O C l_{3}

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C H_{3} C O C l + C_{6} H_{5} C O C l + P O C l_{3}

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C_{2} H_{5} C l + C_{6} H_{5} C O O H + P O C l_{3}

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Solution

The correct option is B $C_{2} H_{5} C l + C_{6} H_{5} C O C l + P O C l_{3}$
Ethyl benzoate reacts with $P C l_{5}$ to give $C_{2} H_{5} C l + C_{6} H_{5} C O C l + P O C l_{3}$
$C_{6} H_{5} C O O C H_{2} C H_{3} + P C l_{5} \to C_{2} H_{5} C l Ethyl chloride + C_{6} H_{5} C O C l benzoyl chloride + P O C l_{3} phosphorous oxy chloride$

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