Ethyl ether when reacted with chlorine in dark yields

{C H}_{3} C H C l O {C H}_{2} {C H}_{3}

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{C H}_{3} {C H}_{2} O {C H}_{2} {C H}_{2} C l

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C l {C H}_{2} {C H}_{2} O {C H}_{2} {C H}_{2} C l

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{C H}_{3} C H C l O C H C l {C H}_{3}

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Solution

The correct option is D ${C H}_{3} C H C l O C H C l {C H}_{3}$
Ethyl ether, when reacted with ${C l}_{2}$ in dark, substitution, occurs at $α$ -carbon atoms.

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Similar questions

{C H}_{3} {C H}_{2} {C H}_{2} O {C H}_{3}

{C H}_{3} {C H}_{2} O {C H}_{2} {C H}_{3}

C H_{3} - C H_{2} - C H_{3} | C | C H_{3} C - C H_{2} C l

H_{2} C = C H - C H_{3} + H C l \to

C H_{3} - C H_{2} - C H_{3} | C | C H_{3} - C H_{2} C l

C H_{2} = C H C l

$C H_{3} - C C H + H C l \to$

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