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Reactions of Aryl Amines (Diazo Salts)

Ethyl mercapt...

Question

Ethyl mercaptan is prepared by the reaction of the following, followed by hydrolysis:

C_{2} H_{5} M g B r + {S O}_{2}

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C_{2} H_{5} M g B r + S

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C_{2} H_{5} M g B r + {C S}_{2}

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C_{2} H_{5} M g B r + H_{2} S

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Solution

The correct option is D $C_{2} H_{5} M g B r + S$
Ethanethiol, commonly known as ethyl mercaptan, is a colorless gas or clear liquid with a distinct odor. It is an organosulfur compound with the formula $C H_{3} C H_{2} - S H$ . It can be prepared by
$C 2 H_{5} M g B r + S \to C_{2} H_{5} S M g B r H_{2} O / H^{+} \to C_{2} H_{5} - S H$
Other reactions are
$C 2 H_{5} M g B r + S = C = S \to C_{2} H_{5} - C (= S) - S H$
$C 2 H_{5} M g B r + O = S = O \to C_{2} H_{5} - S (= S) - O H$

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Similar questions

C_{2} H_{5} M g B r

A

B

C

B

C

C_{2} H_{5} M g B r

M e B r

C H_{3} C O O C_{2} H_{5} + H_{2} O H^{+} - ----- \to C H_{3} C O O H + C_{2} H_{5} O H

10

C a C_{2}

C a C_{2} + H_{2} O \to C a O + C_{2} H_{2}

C_{2} H_{2} \to C_{2} H_{4}

n C_{2} H_{4} \to {(C_{2} H_{4})}_{n}

(C_{2} H_{5} C l)

C_{2} H_{4} (g) + H C l (g) ⟶ C_{2} H_{5} C l (g); △ H = - 72.3 k J / m o l

△ U

70 g

73 g

H C L

300 K

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