Question

Ethylene is produced by, $C_4{H}_8\to 2C_2{H}_4$; rate constant $=2.303\times {10}^4{\sec }^{-1}$, After what time the molar ratio of $\frac{C_2{H}_4}{C_4{H}_8}$ attain the value $1.$

• A. $176sec$
• B. $3522sec$
• C. $1661sec$
• D. $1761sec$

Answer 1

The correct option is A $176sec$

Equation:

$C_4{H}_8\to 2C_2{H}_4$

t=0 a 0

t=t (a-x) 2x

$\frac{2x}{a-x}=1$

$x=\frac{a}{3}$

$t=\frac{2.303}{K}log\frac{a}{a-a/3}$

$=\frac{2.303}{2.303\times {10}^4}log\frac{3}{2}=176$

Answer=176 sec

Option A