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Reactions of Aryl Amines (Diazo Salts)

Ethylene reac...

Question

Ethylene reacts with $H B r$ to form ' $X$ '. When ' $X$ ' is reacted with alcoholic $K O H$ , ' $Y$ ' is formed. Here, ' $X$ ' and ' $Y$ ' are :

A

{B r C H}_{2} - {C H}_{2} B r

and

C_{2} H_{2}

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B

C_{2} H_{5} B r

and

C_{2} H_{4}

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C

C_{2} H_{5} B r

and

C_{6} H_{6}

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D

C_{2} H_{3} B r_{3}

and

C_{2} H_{4}

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Solution

The correct option is B $C_{2} H_{5} B r$ and $C_{2} H_{4}$
First step is the addition of $H B r$ across double bond that is electrophillic addition reaction.

$C H_{2} = C H_{2} + H B r \to C H_{3} C H_{2} B r$

Alcoholic $K O H$ when used elimination reaction takes place.

$C_{2} H_{5} B r a l c . K O H - ---- \to C_{2} H_{4} + H B r$

hence, $X$ is $C_{2} H_{5} B r$ and $Y$ is $C_{2} H_{4}$

Option B is correct.

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