Ethylene, when subjected to hydroxylation in the presence of Baeyer's reagent, gets oxidized to:

glyoxal

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glycol

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epoxyethane

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C O_{2}

and

H_{2} O

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Solution

The correct option is C glycol
Hydroxylation of Ethylene takes place in the presence of Baeyer's reagent to give ethylene glycol as:
$C H_{2} = C H_{2} + H_{2} O + [O] B a e y e r^{'} s - ---- \to r e a g e n t C H_{2} (O H) - C H_{2} (O H)$

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Similar questions

Ethylene reacts with Baeyer's reagent to give [CPMT 1988]

V_{2} O_{5}

773 K

C O_{2}

H_{2} O

(in g)

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