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Introduction to E2 Mechanism

Ethylidene ch...

Question

Ethylidene chloride can be prepared by the reaction of $H C l$ and:

C_{2} H_{4}

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C_{2} H_{2}

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C_{2} H_{6}

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all of the above

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Solution

The correct option is C $C_{2} H_{2}$
Ethylidene chloride is 1,1-Dichloroethane.

It is prepared as follows:
$C_{2} H_{2} + H C l ⟶ C H_{2} = C H - C l$

$C H_{2} = C H - C l + H C l ⟶ C H_{3} C H C l_{2}$

Option B is correct.

Suggest Corrections

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