Ethyne on reaction with water in the presence of $H g S O_{4}$ and $H_{2} S O_{4}$ gives:

acetone

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acetaldehyde

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acetic acid

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none of these

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Solution

The correct option is A acetaldehyde
Ethyne $(H - C \equiv C - H)$ reacts with water in the presence of $H g S O_{4}$ and $H_{2} S O_{4}$ to form acetaldehyde $(C H_{3} - C H O)$ .
$H - C \equiv C - H + H_{2} O H g S O_{4} - --- \to H_{2} S O_{4} H - C H = C H - O H tautomerisation - --------- \to C H_{3} - C H O$
A molecule of water is added to $C \equiv C$ triple bond. The intermediate enol tautomerises to aldehyde. Addition of water follows Markovnikov's rule. $H g S O_{4}$ is used as catalyst.

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