Euclid’s division algorithm for 14 and 10 is visualised in the given figure.

Find the value of a × b × c

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Solution

The correct option is A 32

The figure visualises Euclid’s division algorithm for 14 and 10.

⇒ 14 = 10 × 1 + 4

⇒ 10 = 4 × 2 + 2

⇒ 4 = 2 × 2 + 0

Since the remainder is zero, the HCF of 14 and 10 is 2.

Thus, the side length of the smallest square in the figure is 2.

⇒ c = 2

⇒ a = 2 × 2 = 4

⇒ b = 4

Thus, a × b × c = 4 × 4 × 2 = 32

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