Euclids division lemma, the general equation can be represented as .......

a = b \times q + r

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a = b \div q + r

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a = b - q - r

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a = b + q - r

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Solution

The correct option is A $a = b \times q + r$
Euclids division lemma states that for any two positive integers $a$ and $b$ we can find two whole numbers $q$ and $r$ such that $a = b \times q + r$ where $0 \leq r < b .$
Therefore, $A$ is the correct answer.

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Similar questions

In Euclid Division Lemma,

If a < b , what can be said about q and r ?

Prove the uniqueness of $q$ and $r$ in Euclid division Lemma.
i.e., let $a$ and $b$ be any two positive integers there exist unique integers $q$ and $r$ , $a = b q + r, 0 \leq r \leq b$ .

Q. Euclid's division lemma state that for any two positive integera a and b there exist unique integer q and r such that a=bq+r

Write the condition in which r must statisfy a=bq+r

Q. Euclids division lemma states that if a and b are any two

+

ve integers, then there exists unique integers q and r such that :

Euclid's division lemma states that for any positive integers a and b, there exist unique integers q and r such that a = bq + r, where r must satisfy

(a) 1 < r < b (b) $0 < r \leq b$ (c) $0 \leq r < b$ (d) 0 < r < b

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Euclids division lemma, the general equation can be represented as .......

The correct option is A a=b×q+rEuclids division lemma states that for any two positive integers a and b we can find two whole numbers q and r such that a=b×q+r where 0≤r<b.Therefore, A is the correct answer.

The correct option is A $a = b \times q + r$
Euclids division lemma states that for any two positive integers $a$ and $b$ we can find two whole numbers $q$ and $r$ such that $a = b \times q + r$ where $0 \leq r < b .$
Therefore, $A$ is the correct answer.