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Byju's Answer
Standard VIII
Mathematics
Algebraic Identities
Evaluate: 0...
Question
Evaluate:
(
0.3
)
3
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Solution
The above question can be written as,
(
0.3
)
×
(
0.3
)
×
(
0.3
)
First we find the product,
(
3
)
×
(
3
)
=
9
∴
3
×
3
×
3
=
(
9
)
×
(
3
)
=
27
Total number of decimal places in the given product
=
3
So, the product must contain
3
places of decimals
∴
(
0.3
)
3
=
0.027
Suggest Corrections
0
Similar questions
Q.
Without actually calculating the cubes evaluate :
(
0.2
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3
−
(
0.3
)
3
+
(
0.3
)
3
Q.
0.33
÷
3
×
33
+
0.33
−
3.3
=
.
.
.
.
.
.
.
.
.
.
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Q.
If
y
=
(
0.42
)
3
+
(
0.25
)
3
+
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)
3
−
3
×
0.42
×
0.25
×
0.33
(
0.42
)
2
+
(
0.25
)
2
+
(
0.33
)
2
−
0.42
×
0.25
−
0.25
×
−
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×
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, then the value of
y
is :
Q.
Simplify:
(
0.7
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)
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Q.
Insert two irrational numbers between 0.33 and 0.333
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