Evaluate- 0-6 2 0 - 4 - 5 0 - 2

a=(( 0.6 ) ^ 2 ) ^ 0 ( ( 4 · 5 ) ^ 0 ) ^ 2 We know that, a^0=1 a=( 0.36 ) ^ 0 1 a=1 1 a=0 ...

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Byju's Answer

Standard XII

Mathematics

Sum of Infinite Terms of a GP

Evaluate: 0...

Question

Evaluate:
$((0.6)^{2})^{0} - {((4 \cdot 5)^{0})}^{- 2}$

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Solution

$a = ((0.6)^{2})^{0} - {((4 \cdot 5)^{0})}^{- 2}$

We know that, $a^{0} = 1$

$a = (0.36)^{0} - 1$

$a = 1 - 1$

$a = 0$

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Evaluate:((0.6)2)0−((4⋅5)0)−2

a=((0.6)2)0−((4⋅5)0)−2We know that, a0=1a=(0.36)0−1a=1−1a=0

Evaluate:
$((0.6)^{2})^{0} - {((4 \cdot 5)^{0})}^{- 2}$

$a = ((0.6)^{2})^{0} - {((4 \cdot 5)^{0})}^{- 2}$

We know that, $a^{0} = 1$

$a = (0.36)^{0} - 1$

$a = 1 - 1$

$a = 0$