Evaluate 1 – 2sinθ cosθ if sinθ = cosθ.
- 1
0
2
1
We can write 1 as sin2θ + cos2θ
Therefore, 1 - 2sinθ cosθ = sin2θ + cos2θ - 2sinθ cosθ
= (sinθ−cosθ)2
If sinθ = cosθ, (sinθ−cosθ)2 = 0