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Question

Evaluate 1 – 2sinθ cosθ if sinθ = cosθ.


A

- 1

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B

0

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C

2

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D

1

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Solution

The correct option is B

0


We can write 1 as sin2θ + cos2θ

Therefore, 1 - 2sinθ cosθ = sin2θ + cos2θ - 2sinθ cosθ

= (sinθcosθ)2

If sinθ = cosθ, (sinθcosθ)2 = 0


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