As given (1^3+2^3+3^3)^1/2 ⇒ ( 1+8+27 )^1/2 ⇒ 36^1/2 ⇒ ( 6^2 )^1/2 ⇒ ( 6^2·1/2 ) ⇒ 6 ...

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Byju's Answer

Standard XII

Mathematics

Algebra of Complex Numbers

Evaluate 13...

Question

Evaluate ${(1^{3} + 2^{3} + 3^{3})}^{1 / 2}$

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Solution

As given ${(1^{3} + 2^{3} + 3^{3})}^{1 / 2}$
$\Rightarrow {(1 + 8 + 27)}^{\frac{1}{2}}$
$\Rightarrow 36^{\frac{1}{2}}$
$\Rightarrow {(6^{2})}^{\frac{1}{2}}$
$\Rightarrow (6^{2 \cdot \frac{1}{2}})$
$\Rightarrow 6$

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Similar questions

Evaluate (i) $(1^{3} + 2^{3} + 3^{3})^{\frac{1}{2}}$ (ii) ${[5 {(8^{\frac{1}{3}} + 27^{\frac{1}{3}})}^{3}]}^{\frac{1}{4}}$ (iii) $\frac{2^{0} + 7^{0}}{5^{0}}$ (iv) ${[(16)^{\frac{1}{2}}]}^{\frac{1}{2}}$

Q. Simplify :

{(1^{3} + 2^{3} + 3^{3})}^{\frac{1}{2}}

Q. Find the value of

{{(1}^{3} + 2^{3} + 3^{3})}^{\frac{1}{2}}

Q. Find the value of

(1^{3} + 2^{3} + 3^{3})^{\frac{1}{2}}

Q. simplify:
i)

(1^{3} + 2^{3} + 3^{3})^{1 / 2}

ii)

{(\frac{81}{16})}^{3 / 4} \times {(\frac{25}{9})}^{- 3 / 2}

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Evaluate (13+23+33)1/2

As given (13+23+33)1/2⇒(1+8+27)12⇒3612⇒(62)12⇒(62⋅12)⇒6

Evaluate ${(1^{3} + 2^{3} + 3^{3})}^{1 / 2}$

As given ${(1^{3} + 2^{3} + 3^{3})}^{1 / 2}$
$\Rightarrow {(1 + 8 + 27)}^{\frac{1}{2}}$
$\Rightarrow 36^{\frac{1}{2}}$
$\Rightarrow {(6^{2})}^{\frac{1}{2}}$
$\Rightarrow (6^{2 \cdot \frac{1}{2}})$
$\Rightarrow 6$