Evaluate- 13-23-33-43-3-2

The correct option is C 10^ 3 (1^3 + 2^3 + 3^3 + 4^3)^ 3/2 =(1+8+27+64)^ 3/2 =(100)^ 3/2 =(10^2)^ 3/2 =(10)^2 × 3/2 nbsp; nbsp; nbsp; nbsp;[∵ (a^m)^ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Power of a Power

Evaluate:- 13...

Question

Evaluate:- $(1^{3} + 2^{3} + 3^{3} + 4^{3})^{\frac{- 3}{2}}$

$10^{- 1}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$10^{- 2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$10^{- 3}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$10^{- 4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$10^{- 3}$

$(1^{3} + 2^{3} + 3^{3} + 4^{3})^{\frac{- 3}{2}}$
$= (1 + 8 + 27 + 64)^{\frac{- 3}{2}}$
$= (100)^{\frac{- 3}{2}}$
$= (10^{2})^{\frac{- 3}{2}}$
$= (10)^{2 \times \frac{- 3}{2}}$ $[∵ (a^{m})^{n} = (a)^{m \times n}]$
$= (10)^{- 3}$

Suggest Corrections

Similar questions

Evaluate $(1^{3} + 2^{3} + 3^{3} + 4^{3})^{\frac{- 3}{2}} .$

(1^{3} + 2^{3} + 3^{3} + 4^{3})^{- 3 / 2}

Q. Fill in the blanks

(1^{3} + 2^{3} + 3^{3} + 4^{3})^{- 3 / 2} =

______.

Q. Find the sum of

1^{3} + 2^{3} + \frac{3^{3}}{⌊ 2} + \frac{4^{3}}{⌊ 3} + \frac{5^{3}}{⌊ 4} + . . . .

1^{3} - 2^{3} + 3^{3} - 4^{3} + . . . . + 9^{3} =

Join BYJU'S Learning Program

Evaluate:- (13+23+33+43)−32

The correct option is C 10−3 (13+23+33+43)−32 =(1+8+27+64)−32 =(100)−32 =(102)−32 =(10)2×−32 [∵(am)n=(a)m×n] =(10)−3

Evaluate:- $(1^{3} + 2^{3} + 3^{3} + 4^{3})^{\frac{- 3}{2}}$

The correct option is C
$10^{- 3}$

$(1^{3} + 2^{3} + 3^{3} + 4^{3})^{\frac{- 3}{2}}$
$= (1 + 8 + 27 + 64)^{\frac{- 3}{2}}$
$= (100)^{\frac{- 3}{2}}$
$= (10^{2})^{\frac{- 3}{2}}$
$= (10)^{2 \times \frac{- 3}{2}}$ $[∵ (a^{m})^{n} = (a)^{m \times n}]$
$= (10)^{- 3}$