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Question

Evaluate:

(1) 412
(2) 12513
(3) 112
(4) 113
(5) 10012
(6) 100013
(7) 22512
(8) 51213
(9) 6412
(10) 6416


Solution

(1) 412 can be written as the square root of 4.
And 4 = 2 × 2
So, square root of 4 = 2
412=4=2

(2) 12513 can be written as the cube root of 125.
And 125 = 5 × 5 × 5
So, cube root of 125 = 5
12513=1253=5

(3) 112 can be written as the square root of 1.
And 1 = 1 × 1
So, square root of 1 = 1
112=1=1
 
(4) 113can be written as the cube root of 1.
And 1 = 1 × 1× 1
So, cube root of 1 = 1
113=13=1

(5) 10012 can be written as the square root of 100.
And 100 = 10 × 10
So, square root of 100 = 10
10012=100=10

(6) 100013 can be written as the cube root of 1000.

And 1000 = 10 × 10 × 10
So, cube root of 1000 = 10
100013=10003=10

(7) 22512 can be written as the square root of 225.
And 225 = 15 × 15
So, square root of 225 = 15
22512=225=15

(8) 51213 can be written as the cube root of 512.
And 512 = 8 × 8 × 8
So, the cube root of 512 = 8
51213=5123=8

(9) 6412 can be written as the square root of 8.
And 64 = 8 × 8
So the square root of 64 = 8
6412=64=8

(10) 6416 can be written as the sixth root of 64.
And 64 = 2 × 2 × 2 × 2 × 2 × 2
So the sixth root of 64 = 2
6416=646=2


Mathematics
Mathematics(2013)
Standard VIII

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