Evaluate 125 - 38 - 14-

125 38+14 =75 38+28 =75 18 =56 540 =5140 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VI

Mathematics

Addition of Fractions

Evaluate 12...

Question

Evaluate $1 \frac{2}{5} - \frac{3}{8} + \frac{1}{4}$ .

Open in App

Solution

$1 \frac{2}{5} - \frac{3}{8} + \frac{1}{4}$

$= \frac{7}{5} - \frac{3}{8} + \frac{2}{8}$

$= \frac{7}{5} - \frac{1}{8}$

$= \frac{56 - 5}{40}$

$= \frac{51}{40}$

Suggest Corrections

Similar questions

Q. Evaluate:

| 4 - 8 (3 - 12) | - | 5 - 11 | =

Evaluate :

$(i) \frac{3}{7} + \frac{- 4}{9} + \frac{- 11}{7} + \frac{7}{9} (i i) \frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5} (i i i) \frac{4}{7} + 0 + \frac{- 8}{9} + \frac{- 13}{7} + \frac{17}{9} (i v) \frac{3}{8} + \frac{- 5}{12} + \frac{3}{7} + \frac{3}{12} + \frac{- 5}{8} + \frac{- 2}{7}$

Evaluate (i) ${(\frac{1}{3})^{- 1} - (\frac{1}{4})^{- 1}}^{- 1}$ (ii) $(\frac{5}{8})^{- 7} \times (\frac{8}{5})^{- 4}$

Q. Evaluate

(3^{- 1} + 4^{- 1} + 5^{- 12})^{0}

Evaluate the determinant:

∣ ∣ ∣ ∣ \begin{matrix} 8 & 2 & 7 12 & 3 & 5 16 & 4 & 3 \end{matrix} ∣ ∣ ∣ ∣

Join BYJU'S Learning Program

Evaluate 125−38+14.

125−38+14=75−38+28=75−18=56−540=5140

Evaluate $1 \frac{2}{5} - \frac{3}{8} + \frac{1}{4}$ .

$1 \frac{2}{5} - \frac{3}{8} + \frac{1}{4}$

$= \frac{7}{5} - \frac{3}{8} + \frac{2}{8}$

$= \frac{7}{5} - \frac{1}{8}$

$= \frac{56 - 5}{40}$

$= \frac{51}{40}$