Question

Evaluate : $1\frac{3}{7}+2\frac{1}{9}$

Answer 1

Step 1. converting mixed fractions into improper fractions.

$=$$\frac{(1\times 7)+3}{7}$ $+$ $\frac{(2\times 9)+1}{9}$

$=$$\frac{7+3}{7}$ $+$ $\frac{18+1}{9}$

$=$$\frac{10}{7}+\frac{19}{9}$

Step 2. After step 1, we have to take L.C.M of denominators of both fractions.

L.C.M of $7$ and $9$ $=3\times 3\times 7$

$=$$63$

Step 3. After taking L.C.M of $7$ and $9$, following the given calculation.

$=$$\frac{10}{7}+\frac{19}{9}$

$=$$\frac{(10\times 9)+(19\times 7)}{63}$

$=\frac{90+133}{63}$

$=\frac{223}{63}$

Hence, the required is $\frac{223}{63}$.