Simplifying (1+i)6+(1−i)3.
(1+i)6+(1−i)3=((1+i)2)3+13−i3+3i2−3i
=(1+i2+2i)3+1+i−3−3i
=(1−1+2i)3−2−2i
=(2i)3−2−2i
=8i3−2−2i
=−8i−2−2i
=−2−10i