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Question

Evaluate: 1+(1+b)r+(1+b+b2)r2+... to infinite terms for |br|<1.

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Solution

Let S=1+(1+b)r+(1+b+b2)r2+... (i)
rS=r+(1+b)r2+... (ii)
(i)-(ii)
(1r)S=1+br+b2r2+b3r3+...
S=1(1br)(1r)

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