Evaluate 10−1×103×10−5×103
1
10
100
110
Given
10−1×103×10−5×103
⇒ 10−1+3−5+3 [ am×an = am+n]
⇒ 10−6+6
⇒ 100 = 1
Evaluate: (4×103+3×1+1×10−1+6×100)=___
Evaluate : (i) (47)3 (ii) (1011)3 (iii) (115)3 (iv) (1310)3
(5×103+6×1+1×10−2+5×100)=