1002^3=(1000+2)^3 =(1000)^3+2^3+3(1000)^22+3× 1000× 2^2 =1000000000+8+6000000+12000 1006012008 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Mathematics

Algebraic Identities

Evaluate 10...

Question

Evaluate $1002^{3}$

Open in App

Solution

$1002^{3} = (1000 + 2)^{3}$
$= (1000)^{3} + 2^{3} + 3 (1000)^{2} 2 + 3 \times 1000 \times 2^{2}$
$= 1000000000 + 8 + 6000000 + 12000$
$1006012008$

Suggest Corrections

Similar questions

Evaluate : $\int \frac{x^{3}}{(x - 1) (x^{2} + 1)} d x .$

Evaluate $\int \frac{s i n x - x c o s x}{x (x + s i n x)}$ dx.

Q. Evaluate :

Evaluate : $\int_{0}^{π} \frac{x t a n x}{s e c x + t a n x} d x .$ OR Evaluate : $\int_{1}^{4} {|x-1|+|x-2|+|x-4|}dx.$

Evaluate: $\int_{0}^{\frac{π}{2}} \frac{s i n^{2} x}{s i n x + c o s x} d x .$

Evaluate: $\int_{- 1}^{2} (e^{3 x} + 7 x - 5) d x$ as a limit of sums.

$Evaluate : (i) (\frac{2}{- 3} \times \frac{5}{4}) + (\frac{5}{9} \times \frac{3}{- 10}) (i i) (2 \times \frac{1}{4}) - (\frac{- 18}{7} \times \frac{- 7}{15}) (i i i) (- 5 \times \frac{2}{15}) - (- 6 \times \frac{2}{9}) (i v) (\frac{8}{5} \times \frac{- 3}{2}) + (\frac{- 3}{10} \times \frac{9}{16})$

Join BYJU'S Learning Program

Evaluate 10023

10023=(1000+2)3=(1000)3+23+3(1000)22+3×1000×22=1000000000+8+6000000+120001006012008

Evaluate $1002^{3}$

$1002^{3} = (1000 + 2)^{3}$
$= (1000)^{3} + 2^{3} + 3 (1000)^{2} 2 + 3 \times 1000 \times 2^{2}$
$= 1000000000 + 8 + 6000000 + 12000$
$1006012008$